0=-3x^2-24x+170

Solution for 0=-3x^2-24x+170 equation:

0=-3x^2-24x+170

We move all terms to the left:

0-(-3x^2-24x+170)=0

We add all the numbers together, and all the variables

-(-3x^2-24x+170)=0

We get rid of parentheses

3x^2+24x-170=0

a = 3; b = 24; c = -170;
Δ = b2-4ac
Δ = 242-4·3·(-170)
Δ = 2616
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2616}=\sqrt{4*654}=\sqrt{4}*\sqrt{654}=2\sqrt{654}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-2\sqrt{654}}{2*3}=\frac{-24-2\sqrt{654}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+2\sqrt{654}}{2*3}=\frac{-24+2\sqrt{654}}{6}
$